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((3*2^0.5-3)+(2*2^0.5-3)i)^2+(6+10i)((3*2^0.5-3)+(2*2^0.5-3)i)-(26-6i)=0
We add all the numbers together, and all the variables
((3*2^0.5-3)+(2*2^0.5-3)i)^2+(10i+6)((3*2^0.5-3)+(2*2^0.5-3)i)-(-6i+26)=0
We get rid of parentheses
((3*2^0.5-3)+(2*2^0.5-3)i)^2+(10i+6)((3*2^0.5-3)+(2*2^0.5-3)i)+6i-26=0
We calculate terms in parentheses: +(10i+6)((3*2^0.5-3)+(2*2^0.5-3)i), so:We add all the numbers together, and all the variables
10i+6)((3*2^0.5-3)+(2*2^0.5-3)i
determiningTheFunctionDomain 10i+(2*2^0.5-3)i+6)((3*2^0.5-3)
We add all the numbers together, and all the variables
10i+(2*2^0.5-3)i
We multiply parentheses
10i+4i-3i
We add all the numbers together, and all the variables
11i
Back to the equation:
+(11i)
17i+((3*2^0.5-3)+(2*2^0.5-3)i)^2-26=0
We move all terms containing i to the left, all other terms to the right
17i+((3*2^0.5-3)+(2*2^0.5-3)i)^2=26
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